| 比赛 |
2025.12.13 |
评测结果 |
AAAAAAAAAAAAAAAAAAAA |
| 题目名称 |
排列变换 |
最终得分 |
100 |
| 用户昵称 |
李金泽 |
运行时间 |
1.232 s |
| 代码语言 |
C++ |
内存使用 |
9.37 MiB |
| 提交时间 |
2025-12-13 08:42:57 |
显示代码纯文本
#include<cstdio>
#include<cstdlib>
#include<cstring>
#include<algorithm>
#define N 1000005
#define int long long
#define ul unsigned long long
#define db double
#define fo(i,l,r) for(int i=l;i<=r;i++)
#define rf(i,r,l) for(int i=r;i>=l;i--)
using namespace std;
int n,a[N],t[N],sum1[N],sum2[N],ans;
void swap(int &x,int &y){int t=x;x=y;y=t;}
int max(int x,int y){return x>y?x:y;}
int min(int x,int y){return x<y?x:y;}
void ud(int x,int k){while(x<=n)t[x]+=k,x+=x&-x;}
int gs(int x){int sum=0;while(x)sum+=t[x],x&=x-1;return sum;}
int read(){
int sum=0;bool f=0;char c=getchar();
for(;c<48||c>57;c=getchar())if(c==45)f=1;
for(;c>=48&&c<=57;c=getchar())sum=sum*10+(c&15);
return f?-sum:sum;
}
signed main(){
freopen("permutrans.in","r",stdin);freopen("permutrans.out","w",stdout);
n=read();fo(i,1,n)a[i]=read();
fo(i,1,n)
{
if(a[i]>=i)ud(n+i-a[i],1);
sum1[i]=gs(i);
}
fo(i,1,n)t[i]=0;
rf(i,n,1)
{
ud(max(i-a[i]+1,1),1);
sum2[i]=gs(i);
}
fo(i,1,n)
if(sum1[n-i]+sum2[n-i+1]>sum1[n-ans]+sum2[n-ans+1])
ans=i;
printf("%lld %lld",sum1[n-ans]+sum2[n-ans+1],ans);
return 0;
}